5-p=4p^2

Solution for 5-p=4p^2 equation:

5-p=4p^2

We move all terms to the left:

5-p-(4p^2)=0

determiningTheFunctionDomain
-4p^2-p+5=0

We add all the numbers together, and all the variables

-4p^2-1p+5=0

a = -4; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·(-4)·5
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-9}{2*-4}=\frac{-8}{-8}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+9}{2*-4}=\frac{10}{-8}
=-1+1/4
$